Oscillations - Physics Answers

• The amplitude of a particle excunting SHAM with bremsemey of 60tte is 0-0im. The maximum value of acceleration of the putide- = A Hint: A WA • A small bedy of mass 0.10kg is execiting SHAM of appphitusle 10m and period 0.20s. The maximum force acting in dois. A. Hat: F=may A porticle of mass 10g is describring SHM aling a straight line with period of Is and amplitude of Dim. It's kinetic energy. when it is at 5cm form as equilatonin portion is Hint: K.E=1/2mv²; v=WVA-x² A. A body of mass Iky is executing SHM. Its diyahcement y (im) at I seeinds is given by y = Esin (100t + "/4). Its maximum Kinetic energy is. Hont: K.Em = mWA² A. • A mass m is suspended by means of ton corled spring which have the same Unyth in force instant are unstretched andetion Kl and K2 vispeedway. vertical vibrations, the perial will be us in figure. Then When set into A body is exeuntry Sum with an angelor frequency 2001/s. The velouty of the bouly at 20mm displacement, when the amplituds of 60mm is A. Hat: V= co√A A body of mass 5y is executing Stihl about a print with amplitude Wum, Hs maximum velocity is 100m/sec. Its velvety will 50 cm/ser at a distance A. at: v=wJA²=x² • A simple tourmonic oscillator has a period of 0.0ls and an amplitude of 0.2m. The magnitude of the reloaty in mls at the centre of osülletion is A. Het: v=WJA²-2x²; At the centre,x=0 • A particle has SitM. The equation of os motion is: x = 50m (4t-7%), where x is its displacement. If the dispece- ment of the particle is 3 units, then tos velocity is? A. tout: x = Aisin (wt-4); V=WJA- • The amplitude and the periode time of a S.H.M. are 5cm and Gsec respectively. At a distance of 2.5cm away from the mean position, the phase will be: A y=Asinat, where A = 5m, T=6s The equation of motun is: y = 5 sin (2774/6) For y = 2.5cm, 2-5-5.5in (2016) Sin()== t=12sec Phase = wt = t = • A 100 X10 20kg particle is vibrating with SHM with a period of 100X10, and a maximum speed of 100x1ons. Find the maximum displacement of the particle.