University:
Cameron University
Course:
1364 | General Chemistry I
Academic year:

2024
Views:

456

Pages:

2
Author:

hakulap1d

[Potassium chlorate Composition] Molar mass Calculation: KClO3: O2: 39.1 + 35.5 + 48.0 = 122.6 g/mol 32.0 g/mol KClO3(s) → KCl(s) + (3/2) O2 (g) (1 mol (KClO3)) 122.6 - 1mol (KCl) 74.6 = 3/2 mol (O2) = 48.0 Theoretical value of Percentage of Oxygen in Potassium chlorate: 3 × 16.0 × 100 = 39.2% 122.6 Experimental value of Percentage of Oxygen in Potassium chlorate sample: Original Sample Mass − Re sidue Mass × 100 = ? Original Sample Mass Percentage error in oxygen determination by heating potassium chlorate: % O2 by Exp. − % O2 Theori. × 100 = ? % O2 Theori Think about these questions: Same mass Gas Residue + I Heat KClO3 KCl − II (KClO3 + KCl) − (KClO3 + H2O) KClO3 − O2 O2 = KCl − III + = O2 = KCl = O2 + H2O H2O Suppose we have three different KClO3 samples but with same mass. • Case I: Dry pure KClO3 (Releasing oxygen is causing the sample to change its mass after heating) • Case II: Dry impure KClO3 , (contains KCl) (More residues will remain after heating) • Case III: Moisture pure KClO3 (Releasing water vapor and oxygen are causing the sample to change its mass after heating)