Normal Shock - Edubirdie

University:
Duke University
Course:
PHYSICS 814 | Introduction to Fluid Mechanics
Academic year:

2023
Views:

173

Pages:

2
Author:

Pemuda H

What is (max (Pi) max through a standard shock? (Y+1) M (Y-1)M+2 = max 8-16 Must show that fi is increasing Ex. Iniet tans(M²sing-1-1) tano M,-3 F(0)=0 tons (MS-1-1) tano 2 or plot Flo) vs. 2nd flow sees a d=5° Viscous Boundary Layer (4.2) u-dynamic viscosity - Kinematic viscosity For a steady, incompressible flow: au Mass - 77=0 + av ay Momentum - Spy(n)do = + Fs Ucenter = utk dx = Ug Utoputay dy=u+dx+y(u+dx) dy au = u+dx + y dy ay bottom u+2xdx-dy x-mom-pudy-1+plu+dx)dy-1+plu+dx + y dy) (v+aydy)dx-1 -p(u+dx-3ydy) (v) dx-1=-Sprido + Evisc = p (2ux+u+v) dydx=p(u+vy)dxdy = p (v.vu)dkdy uay vay p(u+v)dxdy = - Sprido + Fuise = Exay dy ay Fox pdy- (p+2x dx)dy=-2x. dx dy Fviso = -Tex dx + (Tex+dy]dx=2y dxdy In y-momentum you get ay=0 so p=p(x)→ P dx Bernoulli P+p2 constant and constant Tox = May So now the only unknowns are u and v (2)+-0 (1) u 2x + v ay P p dx +r ayz This is called Integral Boundary Layer Differentiation Boundary Layer Thickness (4.2.1.2.1) S occurs at u=99% le = 0.99 Ue Displacement Thickness (4.2.1.2.2) 8*= So (1-the) dy