Shock Waves 3.4 - Edubirdie

University:
Duke University
Course:
PHYSICS 814 | Introduction to Fluid Mechanics
Academic year:

2023
Views:

293

Pages:

2
Author:

Pemuda H

Shock Waves (3.4) - Normal Shocks (3.4.1) 142 hz u = u, î dy=0 Kdx Steady Flow 9=20 = 10 since dx is so small P2 T2 Sprñdo = 0 -pu,+P2420 = 0 •Spi (vn)do = P + Fs Frise -Spido +P242 = Pauz-pu² = P-P2 2 P₂+1242 = P + Pu² 2 or pu, (uz-U)=P-P2 show that v↓ and P↑ •p(h+2+ge) (in) do = - Wsis =0 -Pu, hoo +2 U2 h200 = 0 T10 T20 • Need to Prove: P2 (1)=√ M Tz P2 P NORT NYRT T = PIR 42 = P2 1+8M² (2) P= 1+8M² = 2 =(2) 1+ YRT, YRT2 2. + P2+U2P2P P = = P2 P+pu² = P2+P₂u²²√ 2 Shock Waves (3.4) - Normal Shocks (3.4.1) 142 hz u = u, î dy=0 Kdx Steady Flow 9=20 = 10 since dx is so small P2 T2 Sprñdo = 0 -pu,+P2420 = 0 •Spi (vn)do = P + Fs Frise -Spido +P242 = Pauz-pu² = P-P2 2 P₂+1242 = P + Pu² 2 or pu, (uz-U)=P-P2 show that v↓ and P↑ •p(h+2+ge) (in) do = - Wsis =0 -Pu, hoo +2 U2 h200 = 0 T10 T20 • Need to Prove: P2 (1)=√ M Tz P2 P NORT NYRT T Uz PR PzRU = PIR 42 = P2 1+8M² (2) P= 1+8M² = 2 =(2) 1+ YRT, YRT2 2. + P2+U2P2P P = = P2 P+pu² = P2+P₂u²²√ 2