University:
Kentucky State University
Course:
CHE 101 | General Chemistry I
Academic year:

2023
Views:

366

Pages:

2
Author:

Nesbyenvkk

STOICHIOMETRY WORKSHEET 1 SOLUTIONS (MASS-MASS) 1. Determine the mass of lithium hydroxide produced when 0.38 grams of lithium nitride reacts with water. Equation: Li3N + H2O -> NH3 + LiOH Step 1: Balance the equation: Li3N + 3H2O -> NH3 + 3LiOH Step 2: Find the molar mass of Li3N: (3*6.94 + 14.01) = 34.83 g/mol Step 3: Convert 0.38 g of Li3N to moles: 0.38 g / 34.83 g/mol ~ 0.01091 mol Step 4: Use the mole ratio from the balanced equation: 1 mol Li3N -> 3 mol LiOH Moles of LiOH = 0.01091 mol * 3 = 0.03273 mol Step 5: Molar mass of LiOH = 6.94 + 16 + 1 = 23.94 g/mol Mass of LiOH = 0.03273 mol * 23.94 g/mol ~ 0.783 g Answer: 0.783 grams of LiOH 2. What mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide? Equation: NaI + Cl2 -> NaCl + I2 Step 1: Balance the equation: 2NaI + Cl2 -> 2NaCl + I2 Step 2: Molar mass of NaI = 22.99 + 126.90 = 149.89 g/mol Step 3: Convert 0.29 g NaI to moles: 0.29 / 149.89 ~ 0.001934 mol Step 4: Mole ratio from the balanced equation: 2 mol NaI -> 2 mol NaCl (1:1) Moles of NaCl = 0.001934 mol Step 5: Molar mass of NaCl = 22.99 + 35.45 = 58.44 g/mol Mass of NaCl = 0.001934 mol * 58.44 g/mol ~ 0.1131 g Answer: 0.113 grams of NaCl 3. Determine the mass of carbon dioxide produced when 0.85 grams of butane (C4H10) reacts with oxygen. Equation: 2C4H10 + 13O2 -> 8CO2 + 10H2O Step 1: Molar mass of C4H10 = 4*12.01 + 10*1.008 = 58.12 g/mol Step 2: Convert 0.85 g C4H10 to moles: 0.85 / 58.12 ~ 0.01463 mol Step 3: Mole ratio: 2 mol C4H10 -> 8 mol CO2 = 1:4 Moles of CO2 = 0.01463 mol * 4 = 0.05852 mol Step 4: Molar mass of CO2 = 12.01 + 2*16 = 44.01 g/mol Mass of CO2 = 0.05852 mol * 44.01 g/mol ~ 2.575 g Answer: 2.58 grams of CO2 4. Determine the mass of antimony produced when 0.46 grams of antimony(III) oxide reacts with carbon. Equation: Sb2O3 + 3C -> 2Sb + 3CO Step 1: Molar mass of Sb2O3 = 2*121.76 + 3*16 = 291.52 g/mol Step 2: Convert 0.46 g Sb2O3 to moles: 0.46 / 291.52 ~ 0.001578 mol Step 3: Mole ratio: 1 mol Sb2O3 -> 2 mol Sb Moles of Sb = 0.001578 mol * 2 = 0.003156 mol Step 4: Molar mass of Sb = 121.76 g/mol Mass of Sb = 0.003156 mol * 121.76 g/mol ~ 0.3842 g Answer: 0.384 grams of Sb