COSMOS: Complete Online Solutions Manual Organization System
Chapter 4, Solution 73.
Free-Body Diagram:
Let D be the intersection of the lines of action
of the three forces acting on the tool.
From the free-body diagram:
yDC =
(14.4 in.) cos 35° = 32.409 in.
xBC
=
tan 20°
tan 20°
yBC = (14.4 in.) sin 35° = 8.2595 in.
α = tan −1
yDC
3.6 in.
− yBC − 1.8 in.
3.6 in.
= tan −1
( 32.409 − 8.2595 − 1.8 ) in.
= 9.1505°
From the force triangle, using the law of sines:
20 lb
A
=
sin α sin 20°
or A = 43.0 lb
80.8° on tool, and A = 43.0 lb
80.8° on rim of can.