COSMOS: Complete Online Solutions Manual Organization System
Chapter 4, Solution 89.
Free-Body Diagram:
Note that the rod is a three-force body. In the free-body
diagram, E is the intersection between the lines of action
of the three forces.
Using triangle ACF in the free-body diagram:
yCF = d tan θ
From triangle CEF:
xFE = yCF tan θ = d tan 2 θ
and from triangle AGE:
cosθ =
Noting that 1 + tan 2 θ = sec 2 θ =
d + xFE
( L2 )
=
d + d tan 2 θ
( L2 )
(1)
1
cos 2 θ
(1) gives
cosθ =
2d 1
L cos 2 θ
, or
2d
L
Using the given values of d = 2.8 in., and L = 10 in.
cos3 θ =
cos3 θ =
2(2.8 in.)
= 0.56
10 in.
cosθ = 0.82426
θ = 34.486°
or θ = 34.5°
COSMOS Chapter 4 Solution 89
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