University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

214

Pages:

5
Author:

Jabin F.

Visual Elements and Text Transcription Section 1 Heading: #Electric field (E) Equation: ⃗E(r,t) = (μ0 / 4πr) * [⃗r × (⃗r × ⃗p(tr))] Calculation: ⃗p(tr) = p0 * cos(ωt - (ωr/c)) * ẑ Calculation: ⃗p(tr) = -p0 * sin(ωt - (ωr/c)) * ẑ Calculation: ⃗p(tr) = -p0 * ω * cos(ωt - (ωr/c)) * ẑ Simplification: ⃗r × (⃗r × ẑ) = sinθ * ϕ̂ Final equation: ⃗E(r,t) = (μ0 * p0 * ω^2 * sinθ * cos(ωt - (ωr/c))) / (4πr) * ϕ̂ Section 2 Reference: Question 82, Page-97 Heading: #Radiation zone Conditions: r >> λ r >> c/ω λ << c/ω Section 1 Equation:

∝ p0 * ωt Given: p0 = 2qd, d = 1 (length of dipole) Calculations: P1 ∝ q1^2 * μ1 * ω1^4 P2 ∝ q2^2 * μ2 * ω2^4 P1 / P2 = (q1^2 * μ1 * ω1^4) / (q2^2 * μ2 * ω2^4) P1 / P2 = (9^2 * μ1 * (5ω)^4) / ((15)^2 * μ2 * (15ω)^4) P1 / P2 = 1/150 Section 2 Calculation: P1 / P2 = 1/150 Conclusion: P2 = 150 * P1 Reference: Question 28, Page-97 Equation: Intensity ∝ (μ0 / 6πc) * (p0^2 / r^2) Calculation: Intensity ∝ (2^2) * (2^2) = 16 times Section 1 Reference: Question 33, Page-97 Diagram: A square loop carrying a current I. Equations: I = I0 * e^(-iωt)

= (μ0 / 6πc) * <(ṗ)^2> p = qd ṗ = qḋ = iωd <(ṗ)^2> = ω^2 * d^2 * I0^2 / 2

= (μ0 * ω^2 * I0^2 * d^2) / (12πc)

/ (d^2) = (μ0 * ω^2 * I0^2) / (12πc) Section 2 Conclusion: μb = ε0 * c^2