Problem Set #2: Gas Pressure Conversions and Calculations

Problem Set #2 Assigned: January 10, 2024 Due: January 12, 2024 at 2:30 pm Upload your answers to the Canvas website. PDF files are preferred, but Microsoft Word, or image files will be accepted. Please check to make sure that your submission is legible. 1. Express (a) 108 kPa in Torr and (b) 0.975 bar in atmospheres. a 1081hPa 108,000Pa 108,000Pa 133.32Pa 810.08torr b 0975bar 97,500Pa 97,500Pa 97.5KPa 97.51hPa 0.962atm 101.32514Pa (2) Consider 131 g of xenon gas in a 1.0 dm3 volume at 25 °C. What pressure does this gas exert if it is behaving as a perfect gas? 1 0.08206 298 IT P p R 8.314Jmol1 k MO 5 25 273 2984 V 1dm I P 24.45 atm (3) A perfect gas undergoes isothermal compression to reduce its volume by 2.20 dm3. The final pressure of the gas is 5.04 bar and its final volume is 4.65 dm3. Please find the original pressure of the gas in (a) bar and (b) atm. 465dm 2.20dm 6.85dm 0.0 14298 p D 3.62bar D initialvolume 0611298 111108 D 3.57atm (4) A car tire was inflated to 24 lb/in2 when the temperature was -5 °C. To what value does the pressure rise if the temperature goes up to 35 °C? 24ps 689 165.36KPa I 3LY v V 1.63at P 1.87at V I 04268 0,9 13.49 (5) A manometer consists of a U-shaped tube containing a liquid. One side is connected to an apparatus and the other is open to atmosphere. The pressure, p, inside the apparatus is found as: p = pex + gh whereby pex is the external pressure, is the mass density of the liquid inside the manometer tube, g = 9.806 m/s2 is the gravitational constant at the earth’s surface, and h is the difference in height of the liquid in the two different sides of the tube. (A) Suppose the liquid in the monometer is mercury, the external pressure is 760 Torr, and the open side of the monometer is 10.0 cm higher than the side connected to the apparatus. What is the pressure inside the apparatus ( Hg = 13.55 g/cm3 at 25 °C)? P Pex pgh P 760torr P 13.55gloms9.806m 5 0im 773.29torr (B) In an attempt to determine R, a student took a container of volume 20.000 dm3 filled with 0.25132g He and hooked it up to a monomer filled with water. The He was initially at 25 °C and 1.00 atm. The far end of the monometer was open to air at 1.00 atm such that h = 0 for the water. Next, the student heated the gas inside the container to 500 °C and measured a height difference, h, of 206.402 cm in the monometer. Find the value of R that would be calculated from this data given water = 0.99707 g/cm3. (6) The gas constant is R = 0.08206 L atm/(mol K). Using proper dimensional analysis to convert your units, show that this is equivalent to R = 8.314 J/mol. Note that 1.000 bar = 0.9869 atm and 1 bar = 105 Pa. (Hint: think in terms of SI units as you convert L bar into units of energy.) 0.08206L.at m moth 0.9869atm 0.08314 Lbar mol k 100joules 8314J Mol k