University:
Campbell University
Course:
CHEM 111 | General Chemistry I
Academic year:

2024
Views:

250

Pages:

3
Author:

Quintin Ware

KEY Limiting Reagent Name - ____________ 1a.) What mass of CS2 is produced when 17.5 equation? Answer – 5 C + 2 SO2 17.5  of C are reacted with 39.5 CS2 + 4 CO . 37.33721898 . 22.18609 . 17.5 . Limiting reagent of SO2 according to the 22.2 b.) What mass of the excess reactant will be left over? Answer – 39.5 37.33721898 2.2 2a.) What mass of NO is produced when 87.0 The reaction is as follows. Answer – 225 225 of Cu are reacted with 225 3 Cu + 8 HNO3 3 Cu(NO3)2 + 2 NO + 4 H2O  . 85.08459616 . 26.78613932 . . Limiting reagent of HNO3? 26.8 b.) What mass of the excess reactant will be left over? Answer – 87.0 85.08459616 1.9 1 3a.) What mass of P4 is produced when 41.5 according to the following equation. Answer – 7.80 7.80 7.80 of Ca3(PO4)2, 26.5 of SiO2 and 7.80 2 Ca3(PO4)2 + 6 SiO2 + 10 C .  of C are reacted KEY P4 + 6 CaSiO3 + 10 CO 40.28982515 . . 23.41558701 . . 8.045495421 . Limiting reagent 8.05 4 b.) How many grams of each excess reactant will remain unreacted? Answer – 41.5 26.5 40.28982515 23.41558701 4a.) What mass of Br2 is produced when 25.0 K2Cr2O7 + 6 KBr + 7 H2SO4 Answer – 1.21 3.08 of K2Cr2O7, 55.0  of KBr and 60.0 4 K2SO4 + Cr2(SO4)3 + Br2 + 7 H2O . 55.0 . 55.0 . 55.0 Limiting reagent of H2SO4 are reacted. 22.66246499 52.88627451 12.30952381 12.3 b.) How many grams of each excess reactant will remain unreacted? Answer – 25.0 22.66246499 2.3 60.0 52.88627451 7.1 2 5.) What volume of CO2 (g) at STP can be made when 0.0250 with 40.0 of O2 C5H12 Answer – of C5H12 (l) ( at STP in the following equation. (g) (l) KEY 626.0 ), is reacted + 8 O2 5 CO2 (g) + 6 H2O (l)  (g) . 0.0250 . . 40.0 24.2870999 . 25.0 . 24.3 6.) If 50.0 of 0.100 HCl is allowed to react with 30.0 of 0.200 NaOH, which is the reactant in excess? Answer – HCl (aq) + NaOH (aq) H2O (l) + NaCl (aq)  Moles of NaCl (Based on HCl) 0.050 Moles of NaCl (Based on NaOH) . 5.00 . 0.030 10 6.00 10 Since NaOH makes more NaCl, the NaOH is in EXCESS 7.) If 0.250 of Ba(OH)2 is mixed with 15.0 Answer – Ba(OH)2 + 2 HBr  of 0.125 , what mass of BaBr2 can be formed? BaBr2 + 2 HOH . 0.250 . 0.0150 . . 0.4335454 0.27853125 0.279 3