University:
Davenport University
Course:
PHYS 220 | Fundamentals of Physics II
Academic year:

2024
Views:

185

Pages:

2
Author:

Dixie Summers

Density Worksheet Physical Science D = m/V **Densities of Common Substances @ 20°C** | Substance | Density (g/cm³) | Substance | Density (g/cm³) | |---|---|---|---| | Hydrogen | 0.000084 | Aluminum | 2.70 | | Oxygen | 0.00133 | Iron | 7.87 | | Ethanol | 0.785 | Copper | 8.96 | | Benzene | 0.880 | Silver | 10.5 | | Water | 1.000 | Lead | 11.34 | | Magnesium | 1.74 | Mercury | 13.6 | | Salt (sodium chloride) | 2.16 | Gold | 19.32 | 1. The ratio of an object's mass to its **volume** is called the density of the object. 2. A kilogram of **lead** occupies a much smaller volume than a kilogram of water, because lead has a much higher density. 3. For the masses and volumes indicated, calculate the density in grams per cubic centimeters. a. mass = 453 g; volume = 225 cm³ ``` ρ = m/V = 453 g / 225 cm³ = **2.01 g/cm³** ``` b. mass = 5.0 g; volume = 10.0 cm³ ``` ρ = m/V = 5.0 g / 10.0 cm³ = **0.50 g/cm³** ``` c. mass = 26.1 g; volume = 2.0 mL ``` ρ = m/V = 26.1 g / 2.0 mL = **13.05 g/mL** ``` 4. If 89.2 mL of a liquid has a mass of 75.2 g, calculate the liquid's density. ρ = m/V = 75.2 g / 89.2 mL = 0.843 g/mL 5. A cube of metal weighs 1450 g when immersed. Calculate the density of the metal. ρ = m/V = 1450 g / 542 mL = 2.68 g/mL 6. Calculate the volume of 50.0 g of each of the following substances: a. sodium chloride p = 2.16 g/cm³ V = m/p = 50.0 g / 2.16 g/cm³ = 23.1 cm³ b. mercury p = 13.6 g/cm³ V = m/p = 50.0 g / 13.6 g/cm³ = 3.68 cm³ c. benzene p = 0.880 g/cm³ V = m/p = 50.0 g / 0.880 g/cm³ = 56.8 cm³ d. silver p = 10.5 g/cm³ V = m/p = 50.0 g / 10.5 g/cm³ = 4.76 cm³ 7. Calculate the mass of 50.0 cm³ of each of the following substances: a. gold m = pV = (19.32 g/cm³) * (50.0 cm³) = 966 g b. iron m = pV = (7.87 g/cm³) * (50.0 cm³) = 394 g c. lead m = pV = (11.34 g/cm³) * (50.0 cm³) = 567 g d. aluminum m = pV = (2.70 g/cm³) * (50.0 cm³) = 135 g 8. A cubic block of one of the substances listed on the chart has a side length of 5.0 cm and a mass of 224 grams. Which material is it? V = L x W x H = 5.0 cm x 5.0 cm x 5.0 cm = 125 cm³ (two sig figs) ρ = m/V = 224 g / 125 cm³ = 1.72 g/cm³ (very close to magnesium) 9. Archimedes was commissioned to determine if the crown given to the king was pure gold or not. If the crown had a mass of 882 grams and displaced 50.0 mL of water, was the crown pure gold? Show the calculation. ρ = m/V = 882 g / 50.0 mL = 17.6 g/mL No, not dense enough!

Density Worksheet Physical Science

Related Documents

Recommended Documents

Description

Related Documents

Want to Download This Document?

Free up your schedule!

Take 5 seconds to unlock