Problem 1.9: Ball Meeting Point - Edubirdie

University:
Georgia Southern University
Course:
ENGR 2232 | Dynamics of Rigid Bodies
Academic year:

2024
Views:

373

Pages:

1
Author:

Jalen W.

Problem 1.9: Ball Meeting Point A ball is thrown vertically upwards with an initial velocity v_{01} = 20 m/s. Two seconds later, a second ball likewise is thrown vertically upwards with v_{02} = 18 m/s. Determine the height H where the two balls meet. Matlab Code: matlab % Given data v01 = 20; % initial velocity of the first ball in m/s v02 = 18; % initial velocity of the second ball in m/s g = -9.81; % acceleration due to gravity in m/s^2 % Using kinematic equations to find the heights reached by the balls % Let s1 and s2 be the heights reached by the first and second balls, respectively % s = ut + (1/2)at^2 % For the first ball t = linspace(0, 5, 1000); % time vector s1 = v01 * t + 0.5 * g * t.^2; % For the second ball t_shifted = t + 2; % shifting time by 2 seconds for the second ball s2 = v02 * t_shifted + 0.5 * g * t_shifted.^2; % Finding the time when the heights are equal % Let's find the index when the absolute difference between s1 and s2 is smallest [min_diff, min_idx] = min(abs(s1 - s2)); time_meet = t(min_idx); % Height where the two balls meet height_meet = s1(min_idx); % Display result fprintf('Height where the two balls meet: %.2f meters\n', height_meet);

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