Equation Sheet Exam 4 c = 2.9979 x 108 m/s ΔG = ΔH - TΔS h = 6.6261 x 10-34 J s ΔG = ΔG° + RT ln Q 23 -1 NA = 6.02214 x 10 mol ΔG° = -RT ln K R = 8.314 J/(K mol) ΔG = RT ln Q/K 1 eV = 1.60218 x 10-19 J ln (K2/K1) = - (ΔH°/R)(1/T2 – 1/T1) -14 Kw = 1.00 x 10 at 25.0°C 14.00 = pH + pOH at 25.0°C pH ≈ pKa – log (HA/A-) ℑ (Faraday's constant) = 96,485 C mol-1 pH= -log [H3O+] pOH= -log [OH-] Electromagnetic Spectrum: Violet ~ 400-430 nm Blue ~ 431-490 nm Green ~ 491-560 nm Yellow ~ 561-580 nm Orange ~ 581-620 nm Red ~ 621-700 nm Complementary Colors: red/green, blue/orange, yellow/violet Kw = KaKb pK = -log K I- < Br- < Cl- (weak field ligands) < F- < OH- < H2O (intermediate) < NH3 < CO < CN- 9 (strong field ligands) 1 Coulomb • Volt = 1 Joule 1 Bq = 1 nuclei/sec 1A = 1C/s 1W = 1 J/s ln = 2.3025851log 1 J = 1 kgm2s-2 x = [-b ± (b2 –4ac)1/2]/2a ax2 + bx + c = 0 Q = It ΔG°cell = -(n)(ℑ) ΔE°cell ΔE°(cell) = E°(cathode) - E°(anode) ΔE° = E°(reduction) – E°(oxidation) ΔEcell = E°cell – (RT/nℑ)lnQ RT/ℑ = 0.025693 V at 25.0 °C ℑ/RT = 38.921 V-1 at 25.0 °C ΔEcell = E°cell – [(0.025693 V)(lnQ)/n] at 25.0°C ΔEcell = E°cell – [(0.0592 V)(log Q)/n] at 25.0°C ln K = (nℑ/RT) ΔE° A = Aoe-kt N = Noe-kt E = hν = hc/λ A = kN c = νλ [A] = [A]oe-kt t½ = ln2 / k 1/[A] = 1/[A]o + kt t½ = 1 / k[A]o

Exam 4 Equation Sheet

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