University:
Purdue University
Course:
CHM 34200 | Inorganic Chemistry
Academic year:

2023
Views:

55

Pages:

2
Author:

Kirsten Leonard

Problem: What is the lattice energy of SrO? Reactions and Energies: Sr(s) → Sr(g): ΔHsub = 152.3 kJ/mol Sr(g) → Sr⁺(g) + e⁻: ΔH1 = 549.5 kJ/mol Sr⁺(g) → Sr²⁺(g) + e⁻: ΔH2 = 1064.2 kJ/mol O₂(g) → 2O(g): ΔHdiss = 498.36 kJ/mol O(g) + e⁻ → O⁻(g): EA1 = -142.5 kJ/mol O⁻(g) + e⁻ → O²⁻(g): EA2 = 844 kJ/mol Sr(s) + 1/2O₂(g) → SrO(s): ΔHf = -590 kJ/mol Calculations: Lattice energy = -ΔHf - ΣΔHion - ΣEA Lattice energy = -(-590 kJ/mol) - (152.3 kJ/mol + 549.5 kJ/mol + 1064.2 kJ/mol) - (-142.5 kJ/mol + 844 kJ/mol) Lattice energy = 3106.68 kJ/mol Diagram: A diagram illustrating the steps involved in calculating lattice energy, including the formation of Sr²⁺ and O²⁻ ions, the breaking of bonds, and the addition of ionization energies and electron affinities. What is the lattice energy of CaCl₂? Reactions and Energies: Ca(s) → Ca(g): ΔHsub = 178.0 kJ/mol Ca(g) → Ca⁺(g) + e⁻: ΔH1 = 590.0 kJ/mol Ca⁺(g) → Ca²⁺(g) + e⁻: ΔH2 = 1145 kJ/mol Cl₂(g) → 2Cl(g): ΔHdiss = 242.6 kJ/mol Cl(g) + e⁻ → Cl⁻(g): EA = -348.7 kJ/mol Ca(s) + Cl₂(g) → CaCl₂(s): ΔHf = -795.0 kJ/mol Calculations: Lattice energy = -ΔHf - ΣΔHion - ΣEA Lattice energy = -(-795.0 kJ/mol) - (178.0 kJ/mol + 590.0 kJ/mol + 1145 kJ/mol) - 2(-348.7 kJ/mol) Lattice energy = 2253.2 kJ/mol Diagram: A diagram illustrating the steps involved in calculating lattice energy, including the formation of Ca²⁺ and Cl⁻ ions, the breaking of bonds, and the addition of ionization energies and electron affinities.

Lattice Energy Solution SrO and CaCl2

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