University:
Santa Fe College
Course:
PHY 2004 | Applied Physics 1
Academic year:

2024
Views:

440

Pages:

7
Author:

Jabin F.

Rectangular Channel Section B A = B.y P = B+2y R= AP = (By)/(B + 2y) P = B+2y Θ p = A/y + 2y for Economic channel Section P↓ OP =0 (+2y) = 0 [[- A/(y ^ 2) + 2 = 0]] B. y = 2y ^ 2 A = 2y ^ 2 mp beta = 2y ** P = B + 2y zy +2y ** p = 4y R= AP = (2y ^ 2)/(4y) R = y/2 hydraulic depth h = D/T = A/T D = (2y ^ 2)/B = (2y ^ 2)/(2y) D = y = 1.5m 4m A = 1.5 * 8 = 6m ^ 2 S_{0} = 1 i000 C = 55 7 it is desired to 1 the of to max. by changing the dimension fer constant find new C/s, Slope, roughrers dimension of channel and ↑ in 8. A, C, S const. Q max =? Q = AV = 6C * sqrt(RS) = 6.55sqrt(6/7 * 1/1000) Q = 9.66m ^ 3 / s R= AP = 6/(4 + 2 * 1.5) R = 6/7 Qmax = Most Economical Section. b^ prime x y' = 6m ^ 2 For Max. ⇒ B=2y A-2 2 * y' * y' = 6 y' = 3 y ^ 1 = 1.732m beta' = 3.464m R' = 6/(beta' + 2 * y') = 6/3.464 + 2 * 1.732 R' = 6/(8.92l) R ^ 1 = 0.866 or R = y/2 R = 1.732/2 R = 0.866 max A.V = 6C * sqrt(RS) = 6 * 55sqrt(0.866 * 1/1000) Q max =9.711 m^ 3 / B