Elastic Scattering

Elastic Scattering => K.E, Total energy & Linear momentum of the system are Conserved. → Inelastic seattering→ Total energy & L.M of the system are Consented. K.E not co The no. of scattered particles per unit time In an incident beam n = No. of scattering centers. Jin = Incident particle flux The no. of incident particles per unit time area per unit time dn = (d sigma/ d omega)n J in dr = dσ/dr proportionality Const. unit of area. = dN/(nJin dΩ) = The no. of particles per unit time per unit scattering centers, per unit incident flux, in a particular dΩ scattered. sigma_T = Total Cross-section T = integral from 0 to pi integral from 0 to 2pi sigma(theta) sin(theta) d(theta) d(phi) If sigma is independent of phi: T = 2pi * integral from 0 to pi sigma(theta) sin(theta) d(theta) The no. of Scattered particles Per unit time, Per Unit Scattering Centers, per unit incident flux f(θ,φ) = Scattering amplitude. Jsc = Scattered Particle flux. = The no. of scattered particles per unit area per unit time = 145c12) dn = Jsc dA = Jsc 2 N = SIN = ∫Jsc. dA = ∫Jsc X47772 There are several mathematical expressions involving variables like r, A, K, and m. The text mentions "elastic scattering" and a concept related to conservation. The handwriting is neat but the content is dense and complex. |psi(o)>=1/sqrt(2)(|1>+|2>) , 1446 14lt) >= 1 HIL> =E11> H/2)=E212) (日吉(11)+万12>) 14(t=T>= (12)-127) ⇒ 1/J2(e^(-(E1T/hbar)|1>+e^(-(E2T/hbar)|2>)=1/sqrt(2)(|1>-|2>) e -LET et -LET 42- = -1 (Ez-E1)==-1 = ±(2n+1)* e \[n=0,1,2,3\] forminimum \[E2-E1=(2n+1)pihbar/T2Pihbar\] \[E2-E1=(2n+i)h/2T\] (E2-E1)= (27+1).7 \[n=0\] h (Ez-E1) mim. (option-c) + (optera) + = J+Jy = A [\frac{(Oue)+4}{paye59}\int\hat{A}=\frac{J_{n}+Jy}{\hbar}] ⇒