University:
University of the People
Course:
HS 4810 | Health and Policy Management
Academic year:

2024
Views:

468

Pages:

3
Author:

amrinderjeet kaur

UNIT 1 LEARNING JOURNAL PART I 1. Define the population in this survey. The population in this survey consists of all families in the Dominican Republic. 2. What is the population parameter estimated in this survey? The population parameter being estimated is the proportion of families in the Dominican Republic that cannot afford an unexpected expense of $300 without taking a loan. 3. What is the point estimate for the parameter? The point estimate for the population proportion is given by: where: X = 232 (number of families who responded they could not afford $300 unexpected expenses without tapping into loans) n = (total sample size) so p = 0.3437 4. What is the statistic used to measure the uncertainty of the point estimate? Compute the statistic. The standard error (SE) is used to measure the uncertainty of the point estimate. It is calculated using the formula: And substituting the values: Would the resulting value change much if we were to use this proportion to recompute the value of the statistic in (d) using p = 0.4 ? If we use p = 4 , the standard error is: PART 2 PART II To construct a 95% confidence interval for the fraction of viewers who visited due to a coupon: 1. Identify the necessary values: ○ Sample size: N = 504 ○ Number of successes: X = 124 ○ Sample proportion: P = 0.246 2. Compute the standard error: 3. Find the critical value (Z-score) for a 95% confidence interval: The Z-score for 95% confidence is 1.96. 4. Compute the margin of error (ME): ME = Z * SE = 0.0376 5. Construct the confidence interval: So, the 95% confidence interval is (0.208, 0.284) or 20.8% to 28.4%. This means we are 95% confident that the true proportion of viewers who visited because of a coupon falls within this range.