Certainly, here's the analysis of the image you provided: Textual Content: Lecture 6 E = hν = hc/λ C = 3 x 10^8 m/s, Planck's constant momentum = wavelength inverse prop. frequency & wavelength inverse prop. λ - short → x-ray, UV, VIS, IR, micro, radio → long → ↓λ momentum ↑ frequency ↑ amplitude = affected high E light: ↑p, ↑h, ↓λ, more perturb, but less resolution low E light: ↓p, ↓h, ↑λ, less perturb, but more resolution for good resolution, λ must be much smaller than visual target atom ≈ 10⁻¹⁰m, so x-rays are needed. Heisenberg uncertainty principle: tradeoff btw accurately knowing location and momentum of a particle (where's going) smaller λ: ↑resolution larger λ: ↓resolution ↑p (↑resolution) -> more effect/disturbing photon to find λ (leaves, changes path) using a λ to find λ (resolve) changes path. Δx ≈ h/Δp = h/mΔv e- charges where it is going (ejects) UNIT 2 INTRO TO QUANTUM MECHANICS emission and absorption experiments emission: result of e- from higher E. (excited) states to lower; energy is released in photon form. absorption: result of e- from a photon being absorbed in, raising an e- from a lower E state to higher E state emission o QUANTIZED o absorption ΔE = hν ΔE = hν

CHEM 1810 - Lecture 5

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