Relation Between Critical Depth and Minimum Specific Energy | Lecture Note - Edubirdie

University:
Santa Fe College
Course:
PHY 2004 | Applied Physics 1
Academic year:

2024
Views:

145

Pages:

6
Author:

Jabin F.

Relation Between Critical Depth and Minimum Specific Energy Rectangular Section -> Q^2 / g = A^3 / T Q^2 / g = B^3 y_c^3 / B y = y_c for E_min (q = Q/B) Q^2 / B^2 = y_c^3 g Q^2 = y_c^3 g Critical depth for Rectangular section. y_c = (q^2 / g)^(1/3) E = y + V^2 / 2g E_min = y_c + V^2 / 2g E_min = y_c + y_c / 2 E_min = 3/2 y_c Fr = 1 V / sqrt(gD) = 1 V / sqrt(gy) = 1 V^2 = gy V^2 / g = y Triangular channel Section -> A = 1/2 x 2my x y = my^2 D = A/T D = my^2 / 2my D = y/2 Q^2 / g = A^3 / T = 2my Q^2 / g = m^2 y_c^6 / (2my_c) Q^2 / g = my_c^5 / 2 Q.5 Q = 4 m^3/s V_c = ? at y_c when E_min. fr = 1 V_c / sqrt(g y_c) = 1 Q = A V Q = B y V Q = B y_c V_c Q = B y_c V_c q = Q/B = 4 / 2.5 y_c = (q^2 / g)^(1/3) y_c = ((4 / 2.5)^2 / 9.8)^(1/3) V_c = 1 * sqrt(9.81 x 0.639) V_c = 2.503 m/s y_c = 0.639 m

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