The Ratio of Velocity in Rectangular Channel | Santa Fe College

University:
Santa Fe College
Course:
PHY 2004 | Applied Physics 1
Academic year:

2024
Views:

377

Pages:

5
Author:

Jabin F.

The Ratio of Velocity in Rectangular Channel (Vc^2 / 2g) / yc = ? yc = (q^2 / g)^(1/3) Q = A * V for critical flow fr = 1 = V / sqrt(gy) 1 = Vc^2 / g yc 1/2 = Vc^2 / 2g yc V^2 / 2g = yc / 2 -> at critical depth Velocity head = 1/2 critical depth => (V^2 / 2g) / yc = 1/2 option B Q.7 If f = 1, The increase in discharge for one meter of width is 40%. then % increase in yc = ? qc1 = (Q^2 / g)^(1/3) q2 = 1.40 q1 yc1 / yc2 = (q1^2 / q2^2)^(1/3) = (q1 / 1.4 q1)^(2/3) yc1 / yc2 = 0.799 => yc2 = 1.25 yc1 % increase in yc = (yc2 - yc1) / yc1 * 100 = ((yc2 / yc1) - 1) * 100 = 25% Fr = v / sqrt(gD) Q = 2 m^3/s y1 = 2y2 Q = AV v = Q/A = Q/(By) = 2/(1 * y) = 2/y = v y2 = g2 E1 = E2 y1 + v1^2/(2g) = y2 + v2^2/(2g) y1 + (Q^2/(2xg)y1^2) = y2 + Q^2/(2gy2^2) y1 - y2 = (q^2/(2g)) * (1/y2 - 1/y1) y1 = 2y2 y2 = (4/(2 * 9.81)) * (1/y2 - 1/(4y2^2)) y2 = 0.534m y1 = 2 * y2 Subcritical, y1 = 1.069m