University:
Santa Fe College
Course:
PHY 2004 | Applied Physics 1
Academic year:

2024
Views:

323

Pages:

7
Author:

Jabin F.

Uniform Flow => dV/dx = 0 dQ/dx = 0 (SF) Energy slope line (Sw) water Surface Slope (So) Channel bottom slope. Applying bernoullie eqn at section 1 & 2. z1 + y1 + V1^2/2g = z2 + y2 + V2^2/2g + hf if (y1 = y2, V1 = V2) for Uniform flow for Uniform flow z1 = z2 + hf hf = z1 - z2 Slope = hf/L = (z1 - z2)/L Uniform flow -> A flow is to be Uniform If the property w.r.t. distance i.e. depth of flow, Area of C/S and Velocity of flow are constant. The constant depth in the Uniform flow is known as normal depth (yn). (So) channel bottom (Sw) water surface, and Energy line (Sf) all are parallel. => Slopes are equal. So = Sw = Sf P1 - P2 + w sinΘ - ff = M2 - M1 w sinΘ - ff = 0 w sinΘ = f_f γAL sinΘ = f_f γ = W/AL for very small angle Θ sinΘ ≈ Θ ≈ tanΘ γAL S₀ = f_f The frictional Resisting acting btw the fluid and the channel boundary is balanced by Gravity force. τ₀ = f/8 ρV^2 (Based on Exp. Studies) f/8 ρV^2 = γRS₀ f/8 ρV^2 = ρg RS₀ V^2 = (8g/f) RS₀ V = sqrt(8g/f) sqrt(RS₀) τ₀ = γRS₀ V = C sqrt(RS₀)