University:
Santa Fe College
Course:
PHY 2004 | Applied Physics 1
Academic year:

2024
Views:

126

Pages:

5
Author:

Jabin F.

Parity Reversal: (P) → (-P) Polar vector P → (-P) (polar vector) → E → -E → P → -P → A → -A → J → -J Axial Vector P → (+)P (axial vector) (no sign change) Poynting vector (S) = (1/μ₀)E x B = (-E) x (-B) = E x B = Polar vector S → -S Ques.4 Page-65 ϕ = ∫₀ᵃ ∫₀ᵃ (ky³t²) dxdy = kt²a(y⁴/4)₀ᵃ = kt²a⁵/4 ε = -∂ϕ/∂t = -kta⁵/2 Ans. Ques.10 Page-66 #if r < a Ienc = 0, B = 0 #if a < r < b, Ienc = I, B = μ₀I/(2πr) #if r > b, Ienc = I - I = 0, B = 0 # Magnetic energy U = (1/2μ₀) ∫B²dV dV = rdr dφ dz dz = y dr (2πrL) → U = (1/2μ₀) [∫₀ᵃ B₁²πrLdr + ∫ₐᵇ B₂²πrLdr + ∫ᵇᶜ B₃²πrLdr] → U = (1/2μ₀) [∫₀ᵃ (μ₀I/(2πr))²πrLdr + ∫ₐᵇ (μ₀I/(2πr))²πrLdr] → U = (μ₀I²L/4π) ∫ₐᵇ (1/r)dr → U = (μ₀I²L/4π) ln(b/a)