Lecture 4: Permanent Magnets

Parmanent magnets always have two poles magnets • . Neth South ↳ , there exsist ↳ c- N ← s magnetic . 5µF w → µ s pants to the A permanent magnets Northpole • monopole s → N i s magnetic no south pole) Earth's geographical North (which . Electric feild charged objects • told creates electric feild results In turn, Edensity of line • Higher • in a force • current Amount of Electricity Charges → Moving charges → . . a compass needle folds magnetic . . deflection /direction depend and . makes magnetic tends Electric current deflect → electric current create • space Electric points (4)→ f) * Electric throughout charges on feild stronger = that permeates magnetism electric feild, on . → force charge on magnetic feild → force charges on Electromagnetism physical : the diroebn of the current . moving . interaction between charged particles . . . is The • product vector cross two vectors Consider . ñ and b→ . The cross product of it and I E=Éb YÉ axb Magnitude 14--1 all the = bl Sino area The direction perpendicular to > a→ ✗ 5 ' ✗ a- a- I if ex) ixi ix > kxi ) if ex ✗ jxj = - = Jxk = - = = ñ and be formed by ñ and b→ followed by right hand rule . I xñ =o 0 = = ⇒ kxk J✗ I k✗J - x-p ' - = parallelogram of = Fell -5 (A is pureHel to B) =0 K = f i " %☒ i ✗ k=J ( asci -1 AYJ tazk ) ✗ ( bxitbyjtbzk) caxbz-azbylitlazbx-ax.bz/jt(ax-by-ay-bx)k.axbbc--aybz-a2 = by azbx-axbzaxbtz-axby-ayb.sc axbly = tone Magnetic • The • . feild Krauss = → Magnetic force 1-7=45 Ñ× sin ① ✗ is define the a magnetic feild 1J experience unit ' ( angle between i and B) of BET ] tesla . Nslcm N /am , . = circular Moton acceleration that results MUND charged particles path ofthe radius can in > unit causes A We T 48×15 = charged particles r = velocity 10-4-1 Radius of t that travel with 4 > É This allows to Tesla [T] . charge magnitude Magnetic • charge on Particles with a magnetic force . in circular motion at constant speed v. That . moving ← in a uniform magnetic feild will move in cyclotron radius . MI 14113 calculate the period T 1- = Zim 11413 . retired to complete one circular orbit circular From the period we , 7- neither Tor f ex) Proton with Ñ = could calculate cyclotron frequency . ¥¥⇒t=÷=¥÷_ depends oh r or v. velosrly 1,7×106 -10.8×106 J -14.5×101 K through magnetic feild - , moves B. = 0<17 it 0.5J -10.1k T calculate the force of the photon . 9 ([0.8×106×0.1] [4.5×105×05] ) it( [4.5×105×0-7] - = ( 9.2 i -12.32J -14.64h ) 11=-51 = FÉItFbT ✗ to = -14N 10.6×10 -14N - [1.7×1040.1]/1,4 ([1.1×106×0.7] E- 8×06 - * 051) lev ? " " i energy aimed in movy 4W = : ? ou = - you = = , B→E a) what is b) Compare a) É = ( Fb) FB mux Fb ¢v→ xD Yamani Max Max = = = = b) Fy = Ee to ⇒ ⇒ = Electron enemy, 5×10-5-1 = Fy =/ Kev . . maxclt-BD-4.DE v=f÷T 4 BE 1.6×10-14×5×10-5 4.5×10-6 µ ✗ ÑÉ?¥÷¥¥ . mxg = 9.1×10-31×9.81 stronger than force of - = 8.9×10-30 N gravity . by an electron . -4 ( W) (1.6×10-144) 116×10--1^-5 = lev . e) Mass separating isotopes includes singly charged Hel isotopes spectrometer Beams for . . Ht Dt = Mp =p 617×10 -217kg . = Mp -1mn =3 . what . . is 34×10-27kg . the separator between the isotopes - E- when they hit the D= ① photographic plate IT ☐ I vi. 1×106 I r= :* (2+2-124)=2 ( ra r - , ) = = = 2¥pM( a- MY 2(¥¥÷⇒ ( 3.34×10-4 021m - 1.6×10-2 ") P? ext Microwave • in B a feild wth frederic, f = ?-4GHz . D= ? b) The electron What a) . produced by electrons circlemy Microwaves a) oven is in a move circular tube " : the muy electron E ? . f--2.4GHz a. ⇐ D= = "m¥ a ¥ma2 2.4×109*9.1×10>1×222 I. 6×10-19 = 0-086-1 . btr-d-a-Yf. f r -4%-3 F- = Yzmv ' = = = = %m(¥m⇒ 1km #¥É¥ Yzm ( fad/ 2 1.6×10 -16J . magnetron " : May diameter d--2.5mm . ext Interstellar B field f--42MHz cyclotron radiation from electrons : 1- 42MHz = 4.2×109 = D= = D= ? ¥¥m 2%2 2*4.2×10 ") (9.1×10-31) = 1.6M¥ 1.5×10-3 -1 = ) ex straight proton . a) orbital radii bl what E field . is needed to make sure f ff ④ r= . proton continue E- lost :* =¥::÷¥i:÷ 10.4m = b) FÉ 48×15 . ' 4 v13 = = - ICE É= → - E GET = v13 = 0.14m . in a straight line ! Force • • . charged particles In presence of In presensence an . electric feild É=¢E→ of . . magnetic feild . É=qv→×☐→ In pretense of electric ' F- = magnetic feild and . 4É -148×5 " • force 1=4 → = Ñd×B→ Force • → one on on charge . OQ i. total number . F-io.la/---ZqEI=(udxT3)bQL.--(NdxB)Io-Lu Current amount of = -1=0%-1 → charge within L of the conductor f- total charge =(Vd×Ñ) Iota crossing > Iwo -4×5 :L iidot = - . - : - F total ILxB→ f- total JEB ✗Sino = = . area A per unit time .