What F = is the force net on a current loop in uniform spatially a magnetic Feild ? KXB → Ñ → I → | ↳ → It n → ID " → IA → IÑ IAH -113=0 ILD =/1=1 243=11--1 f- net - - f- left # Fright -0 - . 9 pm " tf maximum torte Net force -0 "" " - E- M=Ñ I [ =/UP = 11=11%51^0--1 @ 1) I i. 11=21 § sino = r Net torte =/ 0 B.Ifasm -0 . total torte . . ju will try to line feild B→ . up with magnetic Magnetic dipole moment • NT IA = the is . may-hetdiemome-t.it vector perpendicular to right hand rule is a a plane a of loop current the loop . . The direction of it is given by . when there M is a INA - ext what the is against gravity ? A coil magnitude rod direction of the current I needed to suspend the and B • • X_€m=l8y ✗ 1- ✗ ✗ 20cm FB = = IF Fg -1 fFy 11×13 ILBK Fy my = . = - ] my KT FB = - Fy ⇒ IIB I = = my 1¥ go.LY?j?*-.--s-.aA . a ex) Force on a wire a) is Fp = 13=11%4 = = b) mat (¥ ) Max ILD . " % a) D= ? b) what . ⇒ if we reorient the 11%1=143 Sino ¥0 0-31-15*25 ✗ 0.044T ¥f=IDsmqO°= IB = = 15×0.049 0.73 Mm wire ? " " ext Rectangular loop a) in ? . = b) what a) at It D= 057 in - is É 0=260-6 of loop , 3cm gem ? INA II. 2) ( 60/(005×003) = b) 0-108 A m2 É=µÑ = @ . ) (0.438×(05140.894×9.5)) 108 ftp.Bxi-B.zki-5/n26B-Cos26B-#-L--O.O24jNm ex) Electric motor IV a) Ñ= ? b) Matt ) at a- - Ft - - INA 5×100 - (0¥14 0.35A m2 = É=Ñ×B→⇒Écmad=Ñ×Ñ 0.35×0-12 = = exj I -550A H D-3cm = b) Eg 13=0-127 Ankle 0.042 Nm joints N . -1501 ② - d -15mm I= ? [ = MB LINA)( D) . = IN "¥B " " ¥, =¥¥¥oÉxo = 0.53A I =3 D= . / hmm 220Mt magnetic feild in circular loops Centered on The direction of the magnetic feild depends on the direction of the Increase the current I results in stronger magnetic feild Increase in distance results weaker magnetic feild Currents from • • . creates wire a . a wire . current . . . . D= " - No Magnetic • vs = 44×10 feild electric Electric feild for a - - For infinity long B- . infinity E- TmfA long charge line of . ← YI wire with current I ← 0 MI if 2 Jcr superposition of B- feild Magnetic point told obey in space can the , . - - f) ¥ . superposition principle the : " het vector be obtained from the -515 feild is given magnetic individual sum . of at contributing a folds . Fei Ids and wire force creates B- tends expreienle force wire Magnetic force Consider the D= → in B- feild → F total =/LBSin -0 between two parallel conductors feild Be generated by 1 , this . magnetic a causes force on the wire , 12 . * I/ ^ 1. f- total ←g ¥ ILXB = B. pants into L points up F pants left i. . B. Fa Izl = = Iz L ✗ ✗ B I 1315in ② =IaL×('¥÷) Force =÷) 'per length Tg¥¥ = -1¥ - = ,, . carrying F C- % t i It I , and Iz i same direction , is in If I, and -4 the F different dieobn, the in is t Watt Balance the force between two and the columbs wires is used attractive is repulsive F is . • →F . . the basis for the 51 definition of the Ampere as . . • It can force w be also of a § used mass is 1^151 A - to define the balanced by the µmpµµÑ ¥-6k E s kilogram using magnetic force a Watt Balance : the . Earth :# D= F- ☐ distance from the wire = =4(K✗l0")(t5✗ 10m = 3×10-51 CITY ( lo) Ñ = -0.3Gt 0.244 ⑦ = tan " = 0.39 ( -8%-1=1420 gravitational B £02m -1 D= 20A %;÷ 0-2×10-3 =(4*Y)# r = 0-2m t.FI Ii ' - , riff 12 ☐ =I¥r FLEEK = 0.25T v -800m¢ D= 1am-70.1m 2A - 0=300 02511800115in 30 I= 0.5T FB=ILB 2A 2×0.570.1 0.3m 0.5 47 0-6