University:
Swansea University
Course:
PM-149 | Genetics, Genomics & Evolution
Academic year:

2023
Views:

334

Pages:

6
Author:

Amal Jith

Hardy weinberg EquilibriumN=100Pta= 1P=0.52(Pta)2 = p2+2pata 2=1q=0.5isP20.25mutation frea=25AA = 25Sselectioncoefficient92=0.22 Aa= 50aa = 25= 251002pq= 50P= dominont allele freaq= reccesive allele freq.p2,q2 ,2pqgenotype freqgenotypeof hatelozygersgenotypefreq oftrea ofhomazygous recessivehomozygocsdominant individualindividualsMM=200MN=300NN =100/600calculate the allele freq.0.58(P) M = 200+15P400+300 = 700120012 70600120060100= 350= 0.58600 1213+ 6 12x H 200 4300 /500#21200 An autosomal receisive disorder lay schac's disease frequency in1/3600 how many carriers present in the populationhomono : of receasive individuals = 1/3600q2. tt= /3600a = 1/60 = 0.016no: of caviers 2 apa == 2x59x160x60Ptq = 1= 118P= 1-1360060== 59 =0.9859601182pq = O.D16x0.98x2= 0.03136 + SS 0.0314 x 3600= 113PKO - auteromal receis-25004ax? q2 = I22pa = 2x459 989825002500 25008q= I49O501.49144P= 1-119650240=49 = 2401502500 a 2 1/10,00099xq2pq = 2x9921/10010,000198P= 99= 19810010,00099X899p2= 98011891 810,000 ,8919801+ve assortive matingAAXAAaaxaano real popdation follow H-W4aatallpeople prejertallpeople4AA- ve aisortive matingAAxaatallpeople preffered by shortpeople4AaAa X AaGVL isapoptn = 1/2N+1L-2aaAAAa100= 0.01intreeding decreas genetic variabilityJCAA) = P2+fpqfazinbreeding coefficientf(aa) = 92+fpqf= seffatilization = =1x1 q2J(Aa) = 2pq-tqq=1siblingmating = -0.5x0.5= 0.25first coust D=0.25x0.25=0.0625 A recasive allele cause a disease that has disease freq of 0.01if the fralve in zeco in the poplor then disease freq isq=0.01920.0001= 1/10,000disease frequency.if f= Iq=0.01P=0.99fflaa)q2 = 0.0001+0.0099= 0.01x10,000= 100if f=0.25fpo ==0.0099x0.250.00247522=0.000140.002475= 0.00257a 2610,000 f(Aa) 2pa - 2fpaH= = 2pq - 24alossofheleiozygosit2fpq = 2pq - - Hf= 2pq - H2pqf =1- H2paQnP = 0.3q = 0.7afterfewsgonof intreeding heterozygote freq wasfound to 0.28find intreeding coefficenf= 1- H2pa=1- 0.28 = 1-0.282x0.210.42= 1-133= 1-0.66= 0.34= CQ-33Mfoward motation (4)PaRevease motation (8) (n)nalleleP=rq=qtynty. autoomal locssis91-0.6 = P9,a92=0.4 = qn2x155M=1710-52+1x10-351 = 2x10-5= 23= 0.6650.67

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