University:
The University Of Western Ontario
Course:
Biology 2290F | Scientific Method in Biology
Academic year:

2022
Views:

361

Pages:

2
Author:

Kyuwon J.

BIOL 1001A Session 1 Worksheet – Drug Cocktail Therapy Should HIV drug therapy start early, and why should it be in the form of a drug cocktail? Both answers have to do with evolution of drug resistant mutants. 1. Early treatment: Longer you leave the virus more chance of mutation Assume that 1/5000 virus acquires a mutation that makes it drug resistant. , . At the early stage of an infection, assume a patient is infected with 1000 viruses. How many of those viruses would have the drug resistant mutation? 45060 It makes mutation for drug resistance , would have drug resistance mutation of them because need at least 5000 viruses viruses virus 0%00 = 45-000 therefore 0.2 . none . Assume that 1/5000 virus acquires a mutation that makes it drug resistant. At a later stage of an infection, assume a patient is infected with 10000 viruses. How many of those viruses would have the drug resistant mutation? 45000 It 2 makes mutation virus would viruses be drug for resistance drug resistance, 2/10000 = 45000 therefore . Do you think it’s better to treat early or late? Explain your reasoning. ' always better It is of viral to treat early this makes the mutation variants As the time goes variants to resistance drug generate virus , . would make multiple ' decrease rate . generations making , in the population more chance of . 2. Drug cocktail. Treatment: Assume that 1/1000 virus acquires a mutation that makes it resistant to drug A. Assume also that 1/5000 virus acquires a mutation that makes it resistant to drug B. If a patient is infected with 10000 viruses, then how viruses many would be resistant to drug A only? It ' 11000 resistant to viruses drug A in are resistance for this situation . drug It , 1%000 = ' tooo . therefore 10 virus would be 0.002/10000 If a patient is infected with 10000 viruses, then how viruses many would be resistant to drug B only? 45000 It resistant to viruses drug B in resistant to population of virus this B dry are , 710000=45000 Therefore . 2 virus would be . If a patient is infected with 10000 viruses, then how viruses many would be resistant to both drug A + drug? 45000 is both dry resistant to Yooooooo Yooo virus is 0<00%000 therefore drug = B , resistant to 0.002 dry viruses 240000000 A. So would ward be be resistant to * Population would be too small for to survive any virus Is it better to use drugs singly or as a cocktail? Explain your reasoning. resistant to both dry . . It is better to than multiple drugs use drugs as cocktail Since . virus is more likely be resistance to . Imagine a person has viruses resistant to both drug A and drug B. Can you think another way of treating the person with the same two drugs? (Hint: drugs can be used in a range of concentrations). one dry